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SSC Quantitative Aptitude Speed, Time and Distance Question Bank Speed Time and Distance (I)

  • question_answer
    Deepa rides her bike at an average speed of 30 km/h and reaches her destination in 6 h. Hema covers the same distance in 4 h. If Deepa increases her average speed by 10 km/h and Hema increases her average speed by 5 km/h, what would be the difference in their time taken to reach the destination?

    A) 54 min

    B) 1 h

    C) 40 min

    D) 45 min

    Correct Answer: A

    Solution :

    [a] \[\because \]Distance covered by Deepa with a speed of 30 km/h in 6 h \[=30\times 6=180\,km\] and speed of Hema \[=\frac{180}{4}=45\,km/h\] Now, new speed of Deepa \[=30+10=40\,km/h\] and new speed of Hema \[=45+5=50\,km/h\] \[\therefore \] Time taken by Deepa \[=\frac{180}{40}=4.5\,h\] and time taken by Hema \[=\frac{180}{50}=3.6\,h\] \[\therefore \] Required difference \[=4.5\times 60-3.6\times 60=54\,min\]


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