A) 2
B) \[1\frac{1}{2}\]
C) 3
D) \[2\frac{1}{2}\]
Correct Answer: A
Solution :
[a] \[\because \]\[l=50\,m,\]\[b=44\,m,\]\[h=7cm\] \[=0.07\,m\] \[\therefore \] Volume of tank \[=lbh=50\times 44\times 0.07\] and volume of water flowing per hour \[=\pi {{(7)}^{2}}\times \frac{5000}{10000}\] Hence, required time \[=\frac{\text{Volume}\,\,\text{of}\,\,\text{tank}}{\text{Volume}\,\,\text{of}\,\,\text{water}}\] \[=\frac{50\times 44\times 0.07\times 7\times 10000}{22\times {{7}^{2}}\times 5000}=2\,h\] |
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