SSC Quantitative Aptitude Speed, Time and Distance Question Bank Speed Time and Distance (II)

  • question_answer
    A man started 20 min late and travelling at a speed of \[1{\scriptstyle{}^{1}/{}_{2}}\] times of his usual speed reaches his office in time. The time taken by the man to reach his office at his usual speed is

    A) 40 min

    B) 1 h 20 min

    C) 1 h

    D) 30 min

    Correct Answer: C

    Solution :

    [c] Let usual speed of a man is V and time is t h. By the formula, \[{{V}_{1}}\,{{t}_{1}}={{V}_{2}}\,{{t}_{2}}\]             \[V\,t=1\frac{1}{2}V\,\left( t-\frac{20}{60} \right)\] \[\Rightarrow \]   \[t=\frac{3}{2}\,\left( t-\frac{1}{3} \right)\] \[\Rightarrow \]   \[\frac{3}{2}t-t=\frac{1}{2}\] \[\Rightarrow \]   \[t=1\,h\] Hence, the time taken by the man to reach his office at his usual speed is 1 h.


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