A) 10 s
B) 15 s
C) 18 s
D) 20 s
Correct Answer: D
Solution :
[d] \[\therefore \] Relative speed of train \[=36-9=27\,km/h=\frac{27\times 5}{18}m/s\] and total distance covered = 150 m Hence, required time \[\text{=}\frac{\text{Distance}}{\text{Speed}}\] \[\text{=}\frac{150\times 18}{27\times 5}=20\,s\] |
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