JEE Main & Advanced Mathematics Three Dimensional Geometry Question Bank Sphere

  • question_answer
    If (2, 3, 5) is one end of a diameter of the sphere \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}-6x-12y-2z+20=0\]then co-ordinates of the other end of the diameter are              [Kerala (Engg.) 2005]

    A) (4, 3, 5)

    B) (4, 9, -3)

    C) (4, 9, 3)

    D) (4, 3, -3)

    E) (4, 9, 5)

    Correct Answer: B

    Solution :

                       Equation of sphere is,                    \[{{x}^{2}}+{{y}^{2}}+{{z}^{2}}-6x-12y-2z+20=0\]                    Centre of sphere \[=(3,\,\,6,\,\,1)\]and one end of circle = \[(2,\,3,\,5)\]                    Let other end be\[(x,y,z)\]                    \[\therefore \] \[\frac{2+x}{2}=3,\,\,\,\,\frac{3+y}{2}=6,\,\,\,\frac{5+z}{2}=1\]                    Þ  \[x=6-2\], \[y=12-3\], \[z=2-5\]                    Þ  \[x=4,\,\,y=9,\,\,z=-3\]                    Hence, other end is (4, 9, ?3).


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