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JEE Main & Advanced Physics Ray Optics Question Bank Spherical Mirror

  • question_answer
    The relation between the linear magnification \[m,\] the object distance \[u\] and the focal length \[f\] is

    A)            \[m=\frac{f-u}{f}\]            

    B)            \[m=\frac{f}{f-u}\]

    C)            \[m=\frac{f+u}{f}\]           

    D)            \[m=\frac{f}{f+u}\]

    Correct Answer: B

    Solution :

                       \[\because m=-\frac{v}{u}\] also \[\frac{1}{f}=\frac{1}{v}+\frac{1}{u}\] Þ \[\frac{u}{f}=\frac{u}{v}+1\] Þ \[-\frac{u}{v}=1-\frac{u}{f}\]\[\Rightarrow \frac{-v}{u}=\frac{f}{f-u}\] so \[m=\frac{f}{f-u}\].


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