JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Spring Pendulum

  • question_answer
    One-forth length of a spring of force constant K is cut away. The force constant of the remaining spring will be                                                                                            [MP PET 2002]

    A)            \[\frac{3}{4}K\]                   

    B)            \[\frac{4}{3}K\]

    C)            K    

    D)            4 K

    Correct Answer: B

    Solution :

                       By using \[K\propto \frac{1}{l}\] Since one fourth length is cut away so remaining length is \[\frac{3}{4}th\], hence k becomes \[\frac{4}{3}\]times i.e., \[k'=\frac{4}{3}x\].


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