A) \[\frac{5}{3}\]
B) \[\frac{3}{5}\]
C) \[\frac{25}{9}\]
D) \[\frac{16}{9}\]
Correct Answer: D
Solution :
\[T\propto \sqrt{m}\] Þ \[\frac{{{T}_{2}}}{{{T}_{1}}}=\sqrt{\frac{{{m}_{2}}}{{{m}_{1}}}}\] Þ \[\frac{5}{3}=\sqrt{\frac{M+m}{M}}\] Þ \[\frac{25}{9}=\frac{M+m}{M}\] Þ \[\frac{m}{M}=\frac{16}{9}\]
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