JEE Main & Advanced Physics Simple Harmonic Motion Question Bank Spring Pendulum

  • question_answer
    An object is attached to the bottom of a light vertical spring and set vibrating. The maximum speed of the object is 15 cm/sec and the period is 628 milli-seconds. The amplitude of the motion in centimeters is                                                [EAMCET 2003]

    A)            3.0

    B)            2.0

    C)            1.5 

    D)            1.0

    Correct Answer: C

    Solution :

                       \[{{v}_{\max }}=a\omega =a\frac{2\pi }{T}\]            \[\Rightarrow a=\frac{{{v}_{\max }}T}{2\pi }=\frac{15\times 628\times {{10}^{-3}}}{2\times 3.14}=1.5\,cm\]


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