A) 9/16
B) 25/16
C) 4/5
D) 5/4
Correct Answer: A
Solution :
\[T=2\pi \sqrt{\frac{m}{K}}\] Þ \[m\propto {{T}^{2}}\] Þ \[\frac{{{m}_{2}}}{{{m}_{1}}}=\frac{T_{2}^{2}}{T_{1}^{2}}\] \[\Rightarrow \frac{M+m}{M}={{\left( \frac{\frac{5}{4}T}{T} \right)}^{2}}\Rightarrow \frac{m}{M}=\frac{9}{16}\]You need to login to perform this action.
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