A) \[\frac{{{T}^{2}}}{2x}\]
B) \[\frac{{{T}^{2}}}{2K}\]
C) \[\frac{2K}{{{T}^{2}}}\]
D) \[\frac{2{{T}^{2}}}{K}\]
Correct Answer: B
Solution :
\[U=\frac{1}{2}K{{x}^{2}}\]but\[T=Kx\] So energy stored \[=\frac{1}{2}\frac{{{(Kx)}^{2}}}{K}=\frac{1}{2}\frac{{{T}^{2}}}{K}\]You need to login to perform this action.
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