A) 0
B) 12
C) 13
D) 25
Correct Answer: D
Solution :
[d] \[\sqrt{1+\frac{x}{144}}=\frac{13}{12}\] \[\Rightarrow \] \[\left( 1+\frac{x}{144} \right)={{\left( \frac{13}{12} \right)}^{2}}=\frac{169}{144}\] \[\Rightarrow \] \[\frac{x}{144}=\left( \frac{169}{144}-1 \right)=\frac{(169-144)}{144}\] \[=\frac{25}{144}\]\[\Rightarrow \]\[x=25\] |
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