A) 10000000
B) 999000
C) 999999
D) 990000
Correct Answer: C
Solution :
[c]\[p\,({{p}^{2}}+3p+3)\] \[p=99\] [given] \[=99\,\,[{{(99)}^{2}}+3\times 99+3]\] \[=99\,\,[9801+297+3]=99\,\,[10101]=999999\] |
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