SSC Quantitative Aptitude Basic Calculations Question Bank Square and Cube Root (II)

  • question_answer
    If \[\sqrt{1369}+\sqrt{0.0615+x}=37.25,\] then value of x is

    A) \[{{10}^{-\,\,1}}\]

    B) \[{{10}^{-\,\,2}}\]

    C) \[{{10}^{-\,\,3}}\]

    D) None of these

    Correct Answer: C

    Solution :

    [c] \[\sqrt{1369}+\sqrt{0.0615+x}=37.25\] \[\Rightarrow \]   \[37+\sqrt{0.0615+x}=37.25\] \[\Rightarrow \]   \[\sqrt{0.0615+x}=0.25=\frac{25}{100}=\frac{1}{4}\] \[\Rightarrow \]   \[0.0615+x=\frac{1}{16}\] \[\Rightarrow \]   \[0.0615\times 16+16x=1\] \[\Rightarrow \]   \[\frac{615}{10000}\times 16+16x=1\] \[\Rightarrow \]   \[16x=1-\frac{123}{125}=\frac{2}{125}\] \[\Rightarrow \]   \[x=\frac{2}{125}\times \frac{1}{16}=\frac{1}{1000}\]             \[=\frac{1}{{{(10)}^{3}}}={{10}^{-3}}\]


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