A) \[a=3\]
B) \[3<a<4\]
C) \[a>3\]
D) \[2<a<3\]
Correct Answer: D
Solution :
| [d] \[a=\sqrt{3+a}\]\[\Rightarrow \]\[{{a}^{2}}=3+a\] \[\Rightarrow \] \[{{a}^{2}}-a-3=0\] \[\Rightarrow \] \[a=\frac{1\pm \sqrt{1+12}}{2}=\frac{1\pm \sqrt{13}}{2}\] \[=\frac{1\pm \sqrt{13}}{2}=\frac{1+3.6}{2}=\frac{4.6}{2}=2.3\] \[\therefore \] \[2<a<3\] |
You need to login to perform this action.
You will be redirected in
3 sec
