A) \[2+\frac{1}{\sqrt{2}}\]
B) \[-\frac{1}{\sqrt{2}}\]
C) \[2-\frac{1}{\sqrt{2}}\]
D) \[\frac{1}{\sqrt{2}}\]
Correct Answer: C
Solution :
(c): Rationalizing, we get \[2+\frac{\sqrt{2}}{2}+\frac{2-\sqrt{2}}{2}+\frac{2+\sqrt{2}}{-2}\] \[=2+\frac{\cancel{\sqrt{2}}+\cancel{\sqrt{2}}-\cancel{\sqrt{2}}-2-\sqrt{2}}{2}\] \[=2-\frac{\sqrt{2}}{2}=2-\frac{1}{\sqrt{2}}\].You need to login to perform this action.
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