A) \[\sqrt{2}\]
B) 2
C) 4
D) 8
Correct Answer: B
Solution :
(b) \[\frac{\sqrt{32}+\sqrt{38}}{\sqrt{8}+\sqrt{12}}\times \frac{\sqrt{8}-\sqrt{12}}{\sqrt{8}-\sqrt{12}}\] \[=\frac{(4\sqrt{2}+4\sqrt{3})\times (2\sqrt{2}-2\sqrt{3})}{(8-12)}\] \[=-2\times \left( 2-3 \right)=+2.\]You need to login to perform this action.
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