A) -i
B) 1
C) -1
D) None of these
Correct Answer: C
Solution :
\[{{e}^{iA}}.{{e}^{iB}}.{{e}^{iC}}={{e}^{iA+iB+iC}}={{e}^{i(A+B+C)}}={{e}^{i\pi }}\] [\[\therefore \,A+B+C=\pi \]] = \[\cos \pi +i\sin \pi =(-1)+i(0)=-1\].You need to login to perform this action.
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