A) \[6\]
B) \[5\]
C) \[4\]
D) \[8\]
Correct Answer: C
Solution :
Let 'x? be the required number. Then \[{{x}^{2}}-x=12\] \[\Rightarrow \] \[x\,(x-1)=12\] By inspection, we have \[4(4-1)=12\] \[\Rightarrow \] \[4\times 3=12\] \[\Rightarrow \] \[x=4\]You need to login to perform this action.
You will be redirected in
3 sec