8th Class Mathematics Squares and Square Roots Question Bank Squares and Square Roots

  • question_answer If \[\sqrt{1+\frac{27}{169}}=1+\frac{x}{13},\] what is the value of 'x'?

    A) \[1\]                                    

    B) \[14\]                  

    C) \[10\]                                  

    D) \[12\]                  

    Correct Answer: A

    Solution :

    \[\sqrt{1+\frac{27}{169}}=\sqrt{\frac{196}{169}}=\frac{14}{13}\] \[=1\frac{1}{13}=1+\frac{1}{13}\Rightarrow \,\,x=1\]

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