A) 8, 12, 20
B) 12, 8, 20
C) 20, 8, 12
D) 20, 12, 8
Correct Answer: A
Solution :
Let the numbers be 2x, 3x and 5x. According to question, we have \[{{(2x)}^{2}}+{{(3x)}^{2}}+{{(5x)}^{2}}=608\] \[\Rightarrow 4{{x}^{2}}+9{{x}^{2}}+25{{x}^{2}}=608\] \[\Rightarrow 38{{x}^{2}}=608\] \[\Rightarrow {{x}^{2}}=\frac{608}{38}=16\Rightarrow x=4\] Hence, the numbers are 8, 12 and 20.You need to login to perform this action.
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