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JEE Main & Advanced Physics NLM, Friction, Circular Motion Question Bank Static and Limiting Friction

  • question_answer
    A block of mass 2 kg is kept on the floor.  The coefficient of static friction is 0.4.  If a force F of 2.5 Newtons is applied on the block as shown in the figure, the frictional force between the block and the floor will be          [MP PET 2000]

    A)             2.5 N

    B)             5 N

    C)             7.84 N

    D)             10 N

    Correct Answer: A

    Solution :

                    Applied force \[=2.5\ N\] Limiting friction \[=\mu mg=0.4\times 2\times 9.8=7.84\ N\] For the given condition applied force is very smaller than limiting friction. \[\therefore \] Static friction on a body = Applied force = 2.5 N


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