A) \[\frac{W\sin \alpha }{g\tan (\theta -\alpha )}\]
B) \[\frac{W\cos \alpha }{\cos (\theta -\alpha )}\]
C) \[\frac{W\sin \alpha }{\cos (\theta -\alpha )}\]
D) \[\frac{W\tan \alpha }{\sin (\theta -\alpha )}\]
Correct Answer: C
Solution :
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