A) \[\frac{l}{L}\]
B) \[\frac{l}{L+l}\]
C) \[\frac{l}{L-l}\]
D) \[\frac{L}{L+l}\]
Correct Answer: C
Solution :
\[\mu =\frac{\text{Lenght of chain hanging from the table}}{\text{Lenght of chain lying on the table}}\]\[=\frac{l}{L-l}\]You need to login to perform this action.
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