A) 1 H
B) 4 H
C) \[{{10}^{-3}}\] H
D) \[4\times {{10}^{-3}}\] H
Correct Answer: D
Solution :
\[e=-L\frac{di}{dt}\] but e =4V and \[\frac{di}{dt}=\frac{0-1}{{{10}^{-3}}}=-1/{{10}^{-3}}\] \[\therefore \ \frac{-1}{{{10}^{-3}}}(-L)=4\Rightarrow L=4\times {{10}^{-3}}henry\]
You need to login to perform this action.
You will be redirected in
3 sec
