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JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Static EMI

  • question_answer
    An ideal coil of 10 henry is joined in series with a resistance of 5 ohm and a battery of 5 volt.  2 second after joining, the current flowing in ampere in the circuit will be [MP PET 1995]

    A)            \[{{e}^{-1}}\]                       

    B)            \[(1-{{e}^{-1}})\]

    C)            \[(1-e)\]                                 

    D)            e

    Correct Answer: B

    Solution :

                       From \[i={{i}_{0}}[1-{{e}^{-Rt/L}}]\], where \[{{i}_{0}}=\frac{5}{5}=1\ amp\]            \[\therefore \ i=1\left( 1-{{e}^{\frac{-5\times 2}{10}}} \right)=(1-{{e}^{-1}})amp\]


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