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JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Static EMI

  • question_answer
    A coil of self-inductance 50 henry is joined to the terminals of a battery of e.m.f. 2 volts through a resistance of 10 ohm and a steady current is flowing through the circuit. If the battery is now disconnected, the time in which the current will decay to 1/e of its steady value is               [MP PMT 1996]

    A)            500 seconds                          

    B)            50 seconds

    C)            5 seconds                              

    D)            0.5 seconds

    Correct Answer: C

    Solution :

               Time in which the current will decay to \[\frac{1}{e}\]of its steady value is \[t=\tau =\frac{L}{R}=\frac{50}{10}=5\]seconds 


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