A) \[\frac{1}{2}\]
B) \[\frac{1}{4}\]
C) 2
D) 4
Correct Answer: B
Solution :
\[U=\frac{1}{2}L{{i}^{2}}\ i.e.\frac{{{U}_{2}}}{{{U}_{1}}}={{\left( \frac{{{i}_{2}}}{{{i}_{1}}} \right)}^{2}}={{\left( \frac{1}{2} \right)}^{2}}=\frac{1}{4}\]\[\Rightarrow {{U}_{2}}=\frac{1}{4}{{U}_{1}}\]
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