A) \[2\times {{10}^{-5}}\,henry\]
B) \[3\times {{10}^{-5}}\,henry\]
C) \[4\times {{10}^{-5}}\,henry\]
D) \[6\times {{10}^{-5}}\,henry\]
Correct Answer: B
Solution :
\[{{N}_{2}}{{\varphi }_{2}}=M{{i}_{1}}\Rightarrow 9\times {{10}^{-5}}=M\times 3\] \[\Rightarrow M=3\times {{10}^{-5}}H\]You need to login to perform this action.
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