JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Static EMI

  • question_answer
    The equivalent inductance of two inductances is 2.4 henry when connected in parallel and 10 henry when connected in series. The difference between the two inductances is [MP PMT 2000]

    A)            2 henry                                   

    B)            3 henry

    C)            4 henry                                   

    D)            5 henry

    Correct Answer: A

    Solution :

                       \[{{L}_{S}}={{L}_{1}}+{{L}_{2}}=10H\]                             ..... (i)                    \[{{L}_{P}}=\frac{{{L}_{1}}{{L}_{2}}}{{{L}_{1}}+{{L}_{2}}}=2.4H\]                                         ..... (ii)                    On solving (i) and (ii) L1L2 = 24                ..... (iii)            Also \[{{({{L}_{1}}-{{L}_{2}})}^{2}}={{({{L}_{1}}+{{L}_{2}})}^{2}}-4{{L}_{1}}{{L}_{2}}\] \[\Rightarrow {{({{L}_{1}}-{{L}_{2}})}^{2}}={{(10)}^{2}}-4\times 24=4\]\[\Rightarrow {{L}_{1}}-{{L}_{2}}=2H\]


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