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JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Static EMI

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    An average induced e.m.f. of 1V appears in a coil when the current in it is changed from 10A in one direction to 10 A in opposite direction in 0.5 sec. Self-inductance of the coil is  [CPMT 2001]

    A)            25 mH                                     

    B)            50 mH

    C)            75 mH                                     

    D)            100 mH

    Correct Answer: A

    Solution :

               \[|e|\,=L\frac{di}{dt}\Rightarrow 1=\frac{L\times \left\{ 10-\left( -10 \right) \right\}}{0.5}\Rightarrow L=25mH\]


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