JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Static EMI

  • question_answer
    A coil of resistance 10 W and an inductance 5H is connected to a 100 volt battery. Then energy stored in the coil is [Pb. PMT 2001; CPMT 2002]

    A)            125 erg                                   

    B)            125 J

    C)            250 erg                                   

    D)            250 J

    Correct Answer: D

    Solution :

               \[U=\frac{1}{2}L{{i}^{2}}\Rightarrow U=\frac{1}{2}\times 5\times {{\left( \frac{100}{10} \right)}^{2}}=250J\]


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