JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Static EMI

  • question_answer
    Energy stored in a coil of self inductance 40mH carrying a steady current of 2 A is                                               [Kerala (Engg.) 2001]

    A)            0.8 J                                         

    B)            8 J

    C)            0.08 J                                       

    D)            80 J

    Correct Answer: C

    Solution :

               \[U=\frac{1}{2}L{{i}^{2}}\Rightarrow U=\frac{1}{2}\times 40\times {{10}^{-3}}\times {{(2)}^{2}}=0.08J\]


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