JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Static EMI

  • question_answer
    The current in a coil of inductance 5 H decreases at the rate of 2 A/s. The induced e.m.f. is                           [MH CET 2002]

    A) 2 V

    B) 5 V

    C) 10 V                                         

    D) - 10 V

    Correct Answer: C

    Solution :

    \[e=-L\frac{di}{dt}\], since current decreases so \[\frac{di}{dt}\]is negative, hence \[e=-5\times \left( -2 \right)=+10V\]


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