JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Static EMI

  • question_answer
    When the current change from + 2A to ? 2A in 0.05 second, an e.m.f. of 8 V is induced in a coil. The coefficient of self-induction of the coil is                                                  [AIEEE 2003]

    A)            0.1 H                                        

    B)            0.2 H

    C)            0.4 H                                        

    D)            0.8 H

    Correct Answer: A

    Solution :

               \[e=L\frac{di}{dt}\Rightarrow 8=L\times \frac{\left( 2-\left( -2 \right) \right)}{0.05}\Rightarrow L=0.1H\]


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