JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Static EMI

  • question_answer
    A coil resistance 20W and inductance 5H is connected with a 100V battery. Energy stored in the coil will be [MP PMT 2003]

    A)            41.5 J                                       

    B)            62.50 J

    C)            125 J                                        

    D)            250 J

    Correct Answer: B

    Solution :

               \[U=\frac{1}{2}L{{i}^{2}}=\frac{1}{2}L{{\left( \frac{E}{R} \right)}^{2}}=\frac{1}{2}\times 5\times {{\left( \frac{100}{20} \right)}^{2}}=62.50J\]


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