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JEE Main & Advanced Physics Electro Magnetic Induction Question Bank Static EMI

  • question_answer
    A coil of N = 100 turns carries a current I = 5 A and creates a magnetic flux \[\varphi ={{10}^{-5}}T{{m}^{-2}}\] per turn. The value of its inductance L will be                                                                         [UPSEAT 2004]

    A)            0.05 mH                                  

    B)            0.10 mH

    C)            0.15 mH                                  

    D)            0.20 mH 

    Correct Answer: D

    Solution :

               \[N\varphi =Li\]\[\Rightarrow 100\times {{10}^{-5}}=L\times 5\Rightarrow L=0.2\ mH.\]


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