JEE Main & Advanced Physics Wave Mechanics Question Bank Stationary Waves

  • question_answer
    The equation\[y=0.15\sin 5x\cos 300t\], describes a stationary wave. The wavelength of the stationary wave is [MP PMT 1995]

    A)            Zero                                         

    B)            1.256 metres

    C)            2.512 metres                        

    D)            0.628 metre

    Correct Answer: B

    Solution :

                 On comparing the given equation with standard equation \[\frac{2\pi }{\lambda }=5\] Þ \[\lambda =\frac{6.28}{5}=1.256m\]


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