JEE Main & Advanced Physics Wave Mechanics Question Bank Stationary Waves

  • question_answer
    Two waves are approaching each other with a velocity of 20 m/s and frequency\[n\]. The distance between two consecutive nodes is                                               [Pb. PMT 1999]

    A)            \[\frac{20}{n}\]                   

    B)            \[\frac{10}{n}\]

    C)            \[\frac{5}{n}\]                     

    D)            \[\frac{n}{10}\]

    Correct Answer: B

    Solution :

                         Distance between the consecutive node \[=\frac{\lambda }{2},\]                    but \[\lambda =\frac{v}{n}=\frac{20}{n}\] so \[\frac{\lambda }{2}=\frac{10}{n}\]           


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