A) 0°
B) 90°
C) 180°
D) 360°
Correct Answer: C
Solution :
Both the sides of a node, two antinodes are present with separation \[\frac{\lambda }{2}\] So phase difference between then \[\varphi =\frac{2\pi }{\lambda }\times \frac{\lambda }{2}=\pi \]You need to login to perform this action.
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