A) 3 cm
B) 4.5 cm
C) 6 cm
D) 1.5 cm
Correct Answer: D
Solution :
\[y=5\sin \,\left( \frac{2\pi x}{3} \right)\cos 20\,\pi \,t,\] comparing with equation \[y=2a\sin \frac{2\pi x}{\lambda }\cos \frac{2\pi vt}{\lambda }\]Þ\[\lambda =3,\]distance between two adjacent nodes \[=\lambda /2=1.5cm\].
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