A) 80% and 20%
B) 70% and 30%
C) 55% and 45%
D) 50% and 50%
Correct Answer: A
Solution :
Let the number of male and female employees be x and y respectively. Then \[20800\,x+16800y=20000\,(x+y)\] or \[208x+168y=200(x+y)\] or \[8x=32y\] or \[x=4y\] % of male employees \[=\frac{x}{x+y}\times 100\] \[=\frac{4y}{4y+y}\times 100=80%\] % of female employees \[=\frac{y}{x+y}\times 100\] \[=\frac{y}{4y+y}\times 100=20%\]You need to login to perform this action.
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