A) 6
B) 7
C) 8
D) 12
Correct Answer: B
Solution :
Mid value of a class = 10 Width of class = 6 Let \[{{x}_{1}}\]be the lower limit and \[{{x}_{2}}\]be the upper limit of the class \[\Rightarrow \]\[\frac{{{x}_{1}}+{{x}_{2}}}{2}=10(mid\,point)\] \[\Rightarrow \]\[{{x}_{1}}+{{x}_{2}}=20\] ?.(i) and \[{{x}_{2}}-{{x}_{1}}=6(width)\] ?.(ii) Solving (i) and (ii),we get \[x=7,x{{=}_{2}}13\] Hence, the lower limit of the class is 7.You need to login to perform this action.
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