A) \[\frac{2n+1}{3}\]
B) \[\frac{4n+1}{3}\]
C) \[\frac{{{n}^{2}}{{(n+1)}^{2}}}{2}\]
D) \[\frac{(4n+1)(3n+1)}{7}\]
Correct Answer: A
Solution :
(a): Weighted mean \[=\frac{1.1+2.2+3.3+.....(n-1)(n-1)+n.n}{n}=\frac{\sum\limits_{i=1}^{n}{{{n}^{2}}}}{n}\]
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