A) \[\frac{1}{5}\]
B) \[\frac{2}{5}\]
C) \[\frac{3}{5}\]
D) \[\frac{4}{5}\]
Correct Answer: C
Solution :
Probability of boy being absent \[=\frac{15}{15+10}=\frac{15}{25}=\frac{3}{5}\]You need to login to perform this action.
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