• # question_answer A simply supported beam carrying a concentrated load W at mid-span deflects by ${{\delta }_{1}}$ under the lode. If the same beam carries the load W such that it is distributed uniformly over entire length and undergoes a deflection ${{\delta }_{2}}$ at the mid span. The ratio, ${{\delta }_{1}}:{{\delta }_{2}}$ is: A) 2 : 1                             B) $\sqrt{2}:1$     C) 1.6 : 1              D) 1 : 2

${{\delta }_{1}}=\frac{W{{l}^{3}}}{48\,EI}$ ${{\delta }_{1}}=\frac{5}{348}\,\,\frac{w{{L}^{4}}}{EI}=\frac{5}{348}\,\,\frac{W{{L}^{3}}}{EI}$ ${{\delta }_{1}}:{{\delta }_{2}}::\frac{1}{48}:\frac{5}{348}$ $::1:\frac{5}{8}::1.6:1$