• # question_answer A long helical spring having a spring-stiffness of 12 kN/m and number of turns 20, breaks into two equal parts. The resultant spring stiffness will be: A) 6 kN/m             B) 12 kN/mC) 24 kN/m                       D) 30 kN/m

Correct Answer: C

Solution :

Spring stiffness, $k=\frac{G{{d}^{4}}}{8D_{m}^{3}n}$ $\therefore \,\,\,\,\,\,k\propto \frac{1}{n}$ ${{k}_{2}}=2{{k}_{1}}=24\,\text{N/M}$

You need to login to perform this action.
You will be redirected in 3 sec