A) 0.05 cm
B) 0.1 cm
C) 0.15 cm
D) 0.20 cm
Correct Answer: B
Solution :
\[A=1\,\,c{{m}^{2}},\] l=100 cm, \[E=2\times {{10}^{6}}\text{kgf/c}{{\text{m}}^{\text{2}}}\] W=2000 kgf \[dt=\frac{Wl}{AE}=\frac{2000\times 100}{1\times 2\times {{10}^{6}}}=0.1cm\]You need to login to perform this action.
You will be redirected in
3 sec