A) \[0.425\times {{10}^{-\,3}}\]
B) \[0.5\times {{10}^{-\,3}}\]
C) \[0.585\times {{10}^{-\,3}}\]
D) \[0.75\times {{10}^{-\,3}}\]
Correct Answer: A
Solution :
\[{{\sigma }_{\theta }}=100\,\text{MN/}{{\text{m}}^{\text{2}}}\text{,}\] \[{{\sigma }_{t}}=50\,G\text{N/}{{\text{m}}^{\text{2}}}\text{,}\] \[E=200\,M\text{N/}{{\text{m}}^{\text{2}}}\text{,}\] \[v\text{ }=\text{ }0.3\] \[{{E}_{\theta }}=\frac{1}{E}[{{\sigma }_{\theta }}-v{{\sigma }_{1}}]\] \[=\frac{1}{200\times {{10}^{3}}}[100-0.3\times 50]\] \[=42.5\times {{10}^{-\,5}}\]or\[0.425\times {{10}^{-\,3}}\]You need to login to perform this action.
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