A) \[({{\sigma }_{1}}+{{\sigma }_{2}})/2=\pm \,{{\sigma }_{yp}}/2\]
B) \[{{\sigma }_{1}}/2=\pm \,{{\sigma }_{yp}}/2\]
C) \[{{\sigma }_{2}}/2=\pm \,{{\sigma }_{yp}}/2\]
D) \[{{\sigma }_{1}}=\pm \,{{\sigma }_{yp}}\]
Correct Answer: A
Solution :
According to maximum shear stress theory \[\frac{{{\sigma }_{1}}+{{\sigma }_{2}}}{2}=\frac{{{\sigma }_{yp}}}{2}\]You need to login to perform this action.
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